urgent simple geometry proof (equilateral triangle)
ABC is an equilateral triangle with sides of 2 cm. BC is extended its own length to point D and point E is the midpoint of AB. ED meets AC at point F. Find the area of quadrilateral BEFC in square centimeters in simplest radical form.
I've drawn a figure and everything and tired to proof with a 30-60-90 triangle theorem but nothing is working!! please show me how to solve this using a 2 column proof.
THANK YOU SO MUCH!! really need it before tomorrow morning ><