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Math Help - Proving a parallelogram is a rhombus help, please. So very confused! D:

  1. #1
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    Exclamation Proving a parallelogram is a rhombus help, please. So very confused! D:

    My class is 'learning' about proofs and whatnot, but I can't wrap my head around the problem my teacher assigned us for homework.


    Given: Rhombus ABCD
    Prove: ACE is isosceles

    I know it's isosceles. I mean, it's just one of those things you look at and know. I can't say that, though, and I have no clue where to start or how to go about proving something that seems so obvious to me.


    EDIT: Yo entiendo. 8D
    Last edited by Neon Lolli; May 8th 2008 at 04:11 PM. Reason: I figured it out!
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    Lightbulb

    Staring at the paper did me good.
    I understand it now.
    The meaning is life is just out of reach; nothing will stop me!
    -cackle-

    @______@;;
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  3. #3
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    For a rhombus, the two diagonals of a rhombus bisect each other (i.e. AF = FC) and the intersection of the two diagonals form a right triangle, i.e. \angle EFC = \angle EFA = 90^{\circ}.

    Now, look at triangles AFE and CFE. If you prove that the two right triangles are congruent, then you prove their hypotenuses are congruent and thus, ACE is isoceles. See if you apply the above.
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