Prove that $\displaystyle \frac{BD}{DC} = \frac{PE \cdot AN \cdot ME}{QE \cdot CM \cdot NP}$. (See figure - $\displaystyle f$ is an angle bisector.)

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- May 5th 2008, 12:50 AMjames_bondRatios in a triangle
Prove that $\displaystyle \frac{BD}{DC} = \frac{PE \cdot AN \cdot ME}{QE \cdot CM \cdot NP}$. (See figure - $\displaystyle f$ is an angle bisector.)