Originally Posted by

**Moo** Hello,

A and B are coterminal angles if A-B=360.

Thus it has to be 321 or -321. According to the definition, it'll be -321 degrees 50', since 38-(-321) ~ 360

The problem is that when we are talking about degrees ', the ' corresponds to minutes of degrees. 1 degree makes 60' (1 degree is like an hour). So it can't be -321°50', since 50'+50' $\displaystyle \neq$ 1°=60'.

So it's none of the solutions.

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$\displaystyle \tan(\theta)=-\frac{\sqrt{3}}{3}=-\frac{\sqrt{3}}{\sqrt{3} \cdot \sqrt{3}}=-\frac{1}{\sqrt{3}}$

$\displaystyle \tan(\theta)={\color{red}-\frac 12} \cdot \frac{2}{\sqrt{3}}=\frac 12 \cdot {\color{red}-\frac{2}{\sqrt{3}}}$

Can you continue ?