# Math Help - Simplify square roots....HEELLLPP?

1. ## Simplify square roots....HEELLLPP?

Okay, so ... i dont understand how to do this....???

i did them but i dont know if they are right??

MULTIPLYING------

10. SQ root of 13 x SQ root of 13
i Got 13 on that one.

12. Sq root of 7 x Sq root of 10
i got 5 sq root 7

14.sq root of 3 x sq root of 19
i got Sq root 57

SIMPLIFYING----

18. Sq root 27
i got 3 sq root of 3

20. Sq root 150
i got 2 sq root 75

22 . Sq root 108
i got 3 sq root 4

24. sq root 7500
i got 10 sq rt of 75

If anyone could tell Me if this is right?? If not Show me how?? Thanks!!

2. Originally Posted by n_duncan2010
Okay, so ... i dont understand how to do this....???

i did them but i dont know if they are right??

MULTIPLYING------

10. SQ root of 13 x SQ root of 13
i Got 13 on that one.

12. Sq root of 7 x Sq root of 10
i got 5 sq root 7

14.sq root of 3 x sq root of 19
i got Sq root 57

SIMPLIFYING----

18. Sq root 27
i got 3 sq root of 3

20. Sq root 150
i got 2 sq root 75

22 . Sq root 108
i got 3 sq root 4

24. sq root 7500
i got 10 sq rt of 75

If anyone could tell Me if this is right?? If not Show me how?? Thanks!!
You got some of them right. I'll help explain the ones you didn't:

12) $\sqrt{7}\cdot \sqrt{10} = \sqrt{70}$. You can't simplify it.

20) $\sqrt{150} = \sqrt{25 \cdot 6} = \sqrt{25} \cdot \sqrt{6} = 5 \sqrt{6}$.

22) The answer should be $3 \sqrt{12}$.

3. ## thanks

Thank you

4. Hello, n_duncan2010!

$10)\;\;\sqrt{13} \cdot \sqrt{13}$
i Got 13 on that one. . . . . Right!
$12)\;\;\sqrt{7} \cdot \sqrt{10}$
We have: . $\sqrt{7}\cdot\sqrt{10} \;=\;\sqrt{7\cdot10} \;=\;\sqrt{70}$

$14)\;\;\sqrt{3}\cdot\sqrt{19}$
i got: $\sqrt{57}$ . . . . Yes!

$18)\;\;\sqrt{27}$
i got: . $3\sqrt{3}$ . . . . Good!

$20)\;\;\sqrt{150}$
We have: . $\sqrt{150} \;=\;\sqrt{25\cdot6} \;=\;\sqrt{25}\cdot\sqrt{6} \;=\;5\sqrt{6}$

$22)\;\;\sqrt{108}$
We have: . $\sqrt{108} \;=\;\sqrt{36\cdot3} \;=\;\sqrt{36}\cdot\sqrt{3} \;=\;6\sqrt{3}$

$24)\;\;\sqrt{7500}$

i got: $10\sqrt{75}$ . . . . Keep going!
75 contains a square, too . . .

We have: . $10\sqrt{75} \;=\;10\sqrt{25\cdot3} \;=\;10\cdot\sqrt{25}\cdot\sqrt{3} \;=\;10\cdot5\cdot\sqrt{3} \;=\;50\sqrt{3}$