for the total area of segment AB we have 11+8 = 19 , therefore the area of the rectangle ANDB is 19*8 = 152 and the area of the triangle FDB is (8*8)/2 = 32 = ANG

so subtracting 152 by 2(32) = 88 which is the area of the parallelogram

now for the rectangle we have 11 * 8 = 88