Thread: [SOLVED] semi-circle

1. [SOLVED] semi-circle

hi everyone
please could someone help me with a problem. If i have a semi-circle, and at the baseline , at certain intervals on that baseline, i need to know what the height is to the arc of the semi-circle , at right angles to the baseline , would anyone have a formula i could use

cheers

2. Hello, dnoster!

I have a semicircle, and at certain intervals on the diameter, I have points.
I need to know the height from the points to the arc of the semicircle.
Code:
          C
* * *
*/: \     *
* / :   \     *
* /  :     \    *
/   :h      \
*/    :         \ *
*-----*--+--------*
A  x  P   2r-x    B
A triangle inscribed in a semicircle is a right triangle: . $\angle C = 90^o$

We have a point $P$ on the diameter, where $AP = x.$

If $r$ is the radius of the circle, then $PB = 2r - x$

. . . . . . . . . . . . . . . . . Theorem
. . . . . The altitude to the hypotenuse of a right triangle
. . . . . . . . . . . . .is the mean proportional
. . . . . . . . of the two segments of the hypotenuse.

That is: . $h^2 \:=\:x(2r-x)$

Therefore: . $h\:=\:\sqrt{x(2r-x)}$

3. Originally Posted by dnoster
hi everyone
please could someone help me with a problem. If i have a semi-circle, and at the baseline , at certain intervals on that baseline, i need to know what the height is to the arc of the semi-circle , at right angles to the baseline , would anyone have a formula i could use cheers
Hello,

here is another way to do your problem:
Let the center of your circle be the origin of a coordinate system. Then you can use the Pythagorian theorem:

x-value = b
height to the arc of the semi-circle = a

Then you get:

$a^2+b^2=r^2\ \Longrightarrow \ a=\sqrt{r^2-b^2}$

I've attached a diagram to show what I've calculated.

Greetings

EB