I got everything except for the area can you please help me find the area of the parallelogram?
By pathagoras you ahve $\displaystyle 2x^2=8\sqrt{2}$ solving we get $\displaystyle x=2^{\frac{5}{4}}$ so now looking at the sides the area is $\displaystyle A_{rectangle}=2^{\frac{5}{4}}\cdot(11+2^{\frac{5}{ 4}})$