# Math Help - area of parallelogram

1. ## area of parallelogram

I got everything except for the area can you please help me find the area of the parallelogram?

2. Originally Posted by jwein4492
I got everything except for the area can you please help me find the area of the parallelogram?
By pathagoras you ahve $2x^2=8\sqrt{2}$ solving we get $x=2^{\frac{5}{4}}$ so now looking at the sides the area is $A_{rectangle}=2^{\frac{5}{4}}\cdot(11+2^{\frac{5}{ 4}})$