# area of parallelogram

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• April 21st 2008, 02:51 PM
jwein4492
area of parallelogram
I got everything except for the area can you please help me find the area of the parallelogram?
• April 21st 2008, 03:00 PM
Mathstud28
Quote:

Originally Posted by jwein4492
I got everything except for the area can you please help me find the area of the parallelogram?

By pathagoras you ahve $2x^2=8\sqrt{2}$ solving we get $x=2^{\frac{5}{4}}$ so now looking at the sides the area is $A_{rectangle}=2^{\frac{5}{4}}\cdot(11+2^{\frac{5}{ 4}})$