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Math Help - area

  1. #1
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    area

    I can get everything but the area can you help me?
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  2. #2
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    Hello, jwein4492!

    In the following diagram, NDBA is a rectangle,
    AN = NG,\;BF = DB,\;GD = 11,\;DF = 8\sqrt{2}
    What is the area of parallelogram GDFA ?

    Code:
          A           G      11     D
          * - - - - - * - - - - - - *
          |         *             * |
          |       *         _   *   |
          |     *         8√2 *     | x
          |   *             *       |
          | *             *         |
          * - - - - - - * - - - - - *
          A             F     x     B

    We know the base of the parallelogram: . GD = 11

    We need the height, DB = x.

    Since BF = DB,\;\Delta DBF is a 45 right triangle.

    Using Pythagorus: . x^2 + x^2 \:=\:\left(8\sqrt{2}\right)^2\quad\Rightarrow\quad 2x^2 \:=\:128\quad\Rightarrow\quad x^2 \:=\:64

    Therefore: . x \:=\:8

    Got it?

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  3. #3
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    but

    I got all that I need to find the area.
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  4. #4
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    still need the area of parallelogram

    anyone out there???
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