# Thread: Angles in Parallel Lines

1. ## Angles in Parallel Lines

In this question I have been asked to find a and I need to GIVE REASONS for my arguments.

I have no idea how to find a.

Any help is greatly appreciated, thank you!!

2. Originally Posted by stellina_91
In this question I have been asked to find a and I need to GIVE REASONS for my arguments.

I have no idea how to find a.

Any help is greatly appreciated, thank you!!
Hello stellina,

Where is a?

3. Oops sorry! I meant x, thanks for picking that up

4. Originally Posted by stellina_91
In this question I have been asked to find a and I need to GIVE REASONS for my arguments.

I have no idea how to find a.

Any help is greatly appreciated, thank you!!
If Ay || CD, then the answer is 60 degrees. Because you can extend Ay to meet the other line and then make a parallelogram. After that use parallelogram properties.

5. Oh sorry again, I am supposed to find y

I apologise for any confusion.

6. Originally Posted by stellina_91
Oh sorry again, I am supposed to find y

I apologise for any confusion.
What exactly is y?
Isnt it just 360 - 120 = 240?

7. I'm sorry again! I read the diagram wrong, I'm only supposed to find a, so the a is the x and I have but b in to show my reasons.

Can I then say:

Extending AB out to F:

b = 180 - 120 (adjacent angles on a straight line)
b = 60

Therefore,
a = 60 (opposite angles of a parallelogram are equal)

8. Here is the diagram. Oh now my diagrams aren't showing, I'll start a new post.