Write down the altitude in the special case where s=2b. What type of triangle is this and what is its area? Please help. Thanks.
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Equilateral You tell us the area.
Area = 1/2bh = 1/2 x 2b x a I have no idea, I'm sorry!
What are you not getting? You have it. Simplify and you are done. Do you see that it is equilateral?
Originally Posted by stellina_91 Write down the altitude in the special case where s=2b. Use pythogorus theorem to get the altitude first, then use it to obtain area fully in terms of b.
In the answer it says: This is an equilateral triangle with a = b x root 3 and area = b^2 x root 3. I don't know how they got this.
Originally Posted by stellina_91 In the answer it says: This is an equilateral triangle with a = b x root 3 and area = b^2 x root 3. I don't know how they got this. Do you know Pythogorus theorem? Can you see a right angled triangle in the figure? Now apply Pythogorus theorem to that right angled triangle. And express a in terms of b.
Ohh I see now!! Thanks so much!! Sorry it took me while.
Originally Posted by stellina_91 Ohh I see now!! Thanks so much!! Sorry it took me while. No problem. If you are stuck somewhere, do let us know
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