I believe I have discovered a new triangle center.

Triangle ABC

From A draw AP to BC such as the perimeters of two triangles are equal

From B draw BP to AC such as the perimeters of two triangles are equal

From C draw CP to AB such as the perimeters of two triangles are equal

The three lines intersect at a common point.

I will not post a proof before you have the fun of solving it.

Has anyone ever seen this? Or is this new? Cuz, I never did I searched online for triangular centers.