Hi everyone my name is Rukkk and I am new to this forum I have been trying to solve the below problem but not succeeding. Can anyone help me? Working outs would also be greatly appreciated. Thanks for the help, Rukkk
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if you draw lines down to form a square within the circle you'll see the diameter is 80 and radius therefore 40 then use length of arc formulas?
(r-8)^2 + 32^2 = r^2 a = arcsin 32/r circumference = r*(2*pi - 2*a) sorry I'm in a hurry
Hi! Now I have more time: r = radius a = half the angle AOB (r-8)^2 + 32^2 = r^2 (Theorem of Pythagorah) sin a = 32/r => a = arcsin 32/r circumference = r*2*a (Sorry, wrong last time) Kind regards
Hello, rukkk! Welcome aboard! Code: C * * * * |8 * A* - - - + - - - *B * * |D * * * | *R * * | * * * * * * O * * * * * * * * * * We have a circle with center The radius is: . Chord Since , then In right triangle . .
C * * * * |8 * A* - - - + - - - *B * * |D * * * | *R * * | * * * * * * O * * * * * * * * * *
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