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Math Help - need solutions

  1. #1
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    need solutions

    Two rectangles are similar. If their dimensions are 4 by 5 and y and 5, find the value fo y > 5



    4 coins are labled as 2, 3, 4 and 5. When 2 coins are drawn without looking, what is the probability that their sum is greater than 8?
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  2. #2
    Bar0n janvdl's Avatar
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    Quote Originally Posted by sri340 View Post
    Two rectangles are similar. If their dimensions are 4 by 5 and y and 5, find the value fo y > 5
    Let:
    L_{1} = 4

    W_{1} = 5

    The ratio between L_{1} and W_{1} is  \frac{5}{4}

    Then:
    L_{2} = 5

    W_{2} = \frac{5}{4} \times 5 = \frac{25}{4} = 6,25

    Quote Originally Posted by sri340 View Post
    4 coins are labled as 2, 3, 4 and 5. When 2 coins are drawn without looking, what is the probability that their sum is greater than 8?
    So we have to draw coins 4 and 5.

    The probability of drawing 4 is \frac{1}{4}

    The probability of drawing 5 is \frac{1}{3}

    Multiply the events.

    Probability that sum is greater than 8: \frac{1}{12}

    (By the way, if you draw the 5 first, its probability will be \frac{1}{4}, and of course the probability of drawing a 4 would then be \frac{1}{3}.
    Last edited by janvdl; April 2nd 2008 at 03:22 AM. Reason: Please note i edited my post. Made mistakes.
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  3. #3
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    originally posted by sri340 part b four coins

    four coins 2,3,4,5 are drawn from a box.probability of getting anumber greater than 8.
    there are six outcomes 23,24, 25, 34, 35,45 and only one is favorable.
    probability is thus 0ne in six.


    bj
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