ok, i dont know if im doing this right so i just need it checked by someone who is familiar with the subject.
I'm not sure im doing it right, and since X=47 does that mean the red car's speed is 47miles per hr?
yeap, thats what i got for the 46.96, and i rounded it off to 47. But since
x=47 that means the red car's speed is 47 m/hr? Or do i have to times it by two since the word problem says that "the red car's speed is twice the blue car's speed" or do i divide 47 by half to get the speed of the blue car.
ok i get it now. i did everything you did except where you took (21 X 5)squared
I just took the 105 and squared it, combined the like terms, isolated X by divining both sides by 5 and then finally took the square root of both sides to get the X squared alon and ended up with the rounded off 47. Thanks alot.