attached, find the problem description. Need solution for this.
Follow Math Help Forum on Facebook and Google+
If the square has a perimeter of y, then the side length is (y/4) and the area is (y/4)^2
If AC = 2BC, then the area of the right triangle is (1/2) 2BC x BC, wchich is (BC)^2.
If the areas are the same then:
(y/4)^2 = (BC)^2
y/4 = BC
Imagine it like this...
Here we can clearly see that 4BC makes up the perimeter of the square, Y.
So Y/4 = BC
View Tag Cloud