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Math Help - help me geometry problem

  1. #1
    Member
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    Jan 2008
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    173

    help me geometry problem

    attached, find the problem description. Need solution for this.
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  2. #2
    Junior Member
    Joined
    Mar 2008
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    49

    Any help?

    If the square has a perimeter of y, then the side length is (y/4) and the area is (y/4)^2

    If AC = 2BC, then the area of the right triangle is (1/2) 2BC x BC, wchich is (BC)^2.

    If the areas are the same then:

    (y/4)^2 = (BC)^2

    y/4 = BC
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  3. #3
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    Alfaz del Pi Spain
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    (b) Y/4

    Imagine it like this...


    Here we can clearly see that 4BC makes up the perimeter of the square, Y.

    So Y/4 = BC
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