I assume you're familiar with trig forms for vectors.
The magnitude and direction of two forces acting on an object are:
70 lbs, S 56° E and 50 lbs, N 72° E.
Find the magnitude, to the nearest hundredth of a pound,
and the direction angle, to the nearest tenth of a degree,
of the resultant force.
Answers: 108.21 lbs, S 77.4° ECode:Q | * | * |72°* | * 18° O * - - - - - - - | * 34° |56°* | * | * | * | * P
The object is at .
Rewrite the bearings (angles) relative to the positive x-axis.
The forces are:
. . . . . . . and:
The resultant vector is the sum of these vectors:
The magnitude is: 108.21
The resultant makes an angle with the positive x-axis where:
Therefore, the direction is: S 77.4° E