Hello, CONFUSED_ONE!

I assume you're familiar with trig forms for vectors.

The magnitude and direction of two forces acting on an object are:

70 lbs, S 56° E and 50 lbs, N 72° E.

Find the magnitude, to the nearest hundredth of a pound,

and the direction angle, to the nearest tenth of a degree,

of the resultant force.

Answers: 108.21 lbs, S 77.4° ECode:Q | * | * |72°* | * 18° O * - - - - - - - | * 34° |56°* | * | * | * | * P

The object is at .

Rewrite the bearings (angles) relative to the positive x-axis.

The forces are:

. . . . . . . and:

The resultant vector is the sum of these vectors:

. .

. .

The magnitude is:108.21

The resultant makes an angle with the positive x-axis where:

. .

Therefore, the direction is:S 77.4° E