1. ## Two touching circles...

Fig. shows circles which are just touching. Find x by using pythagoras theorem.

I believe they're tangential circles.

Here's the figure:

p.s. i am a bit bad at drawing on pc. :P

2. You mean something like

?

Being both externally tangent, try to prove a more general result: let $r,R$ be the radii of the circles, then $x=2\sqrt{r\cdot R}\,.$

3. Uhh, no. More like this:

and they're forcing me to use pythogoras theorem somehow

4. Sorry for not being able to easily super/sub script in paint. =)

Edit: Oops, that's supposed to be 25+7.5 for A.

5. Ahh, stupid me. I wasn't getting how to get that B, and now it's all clear. Thanks

6. It regrettable that you did not pickup on Krizalid’s suggestion.
I do not think that he misunderstood the x (though I wish he had used say y).
That is the horizontal distance between the centers in terms of the radii: $2\sqrt {Rr}$.
Now the x in the original problem is $R + 2\sqrt {Rr} + r = \left( {\sqrt R + \sqrt r } \right)^2$.
That is an elegant formula.
Note: $\left( {\sqrt {25} + \sqrt {7.5} } \right)^2 = {\rm{59}}{\rm{.8861278752583}}$

7. After being able to solve few similar problems, I'm stuck again on a problem of somewhat similar nature.

I can't seem to comprehend this circles tangent thing I assume. Here I have to find h using pythagoras theorem again.

Attached is the image of circles.

8. Here ya go: