Thread: Please help me!

Let triangle ABC that M is in the plane of this triangle.
A',B',C'are midpoint in (BC),(AC),(AB).
Prove that MA/MA'=MB/MB'=MC/MC'=2.
Thanks in advance!

Originally Posted by mpgc_ac

Let triangle ABC that M is in the plane of this triangle.
A',B',C'are midpoint in (BC),(AC),(AB).
Prove that MA/MA'=MB/MB'=MC/MC'=2.
Thanks in advance!

By that alone, it cannot be solved. Specify more where exactly is M.

As posted, I can put M anywhere inside or outside of triangle ABC such that MA/MA' is not equal to 2, for example.

Originally Posted by mpgc_ac

Let triangle ABC that M is in the plane of this triangle.
A',B',C'are midpoint in (BC),(AC),(AB).
Prove that MA/MA'=MB/MB'=MC/MC'=2.
Thanks in advance!

Can we assume the M is the centroid, the point of intersection of the
medians AA', BB' and CC'?

RonL

Originally Posted by CaptainBlack

Can we assume the M is the centroid, the point of intersection of the
medians AA', BB' and CC'?

RonL

Yes you are right. Because the ratio from the vertex to the centroid to the remaining distance is 2:1