Let triangle ABC that M is in the plane of this triangle.
A',B',C'are midpoint in (BC),(AC),(AB).
Prove that MA/MA'=MB/MB'=MC/MC'=2.
Thanks in advance!
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Let triangle ABC that M is in the plane of this triangle.
A',B',C'are midpoint in (BC),(AC),(AB).
Prove that MA/MA'=MB/MB'=MC/MC'=2.
Thanks in advance!
By that alone, it cannot be solved. Specify more where exactly is M.Quote:
Originally Posted by mpgc_ac
As posted, I can put M anywhere inside or outside of triangle ABC such that MA/MA' is not equal to 2, for example.
Can we assume the M is the centroid, the point of intersection of theQuote:
Originally Posted by mpgc_ac
medians AA', BB' and CC'?
RonL
Yes you are right. Because the ratio from the vertex to the centroid to the remaining distance is 2:1Quote:
Originally Posted by CaptainBlack