Because t is a real number it is taken to be radian measure.
2 pi corresponds to 360 degrees. So just do the conversions.
Please see the three pictures I enclose!
I wonder what the 't' parameter really is in equations like this for an ellipse:
x = xCenter + longaxis*cos(t)
y = yCenter + shortaxis*sin(t)
To my surprise, it is NOT the straight forward angle I thought it was!
I want a triangle to "take a bite" out of an ellipse. I know the coordinates of its three corners, so I use the law of cosines to calculate the angle A which is at the center of the ellipse. That angle is the measure of the "bite".
Then I draw the ellipse using parametric form. In my Matlab code I let the parameter angle go from 0 to 360-A. When A is 90 degrees or 180 degrees, it works as I want it too. But at for example 135 degrees, it doesn't. The ellipse is not drawn all the way, although I let the parameter t go from 0 to 225 degrees.
So I must have misunderstood how that t-parameter works.
Is there any way for me to transform a t-value to a real angle? For example, what must from 0 to t ust I use, in order for the ellipse to cover 235 degrees?
EDIT:
Of course, Matlab works in radians, I just translate it to degrees here to make it more intuitive.