I have a sphere at origin and a known 3d point outside the sphere.
How do I calc the diameter of the cone created by the 3d point
and it's intersection with the sphere (if that makes sense)
Thanks
Hello,Originally Posted by Blain
I've attached a diagram to show you what I've calculated.
All lines PT form a cone. C is the centre of the sphere. All triangles CTP are right triangles. So the diametre of the cone's base is 2 times the height in the right triangle. The height in a right triangle (and only there) can be calculated by:
$\displaystyle h={{r \cdot TP}\over CP}$
If you know the length of the three lines you only have to plug in the values and caculate the radius of the base.
Greetings
EB