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Math Help - [SOLVED] Geometry help needed... a.s.a.p. I'm in tears!

  1. #1
    Newbie oXCryssieLeahXo's Avatar
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    Exclamation [SOLVED] Geometry help needed... a.s.a.p. I'm in tears!

    So I'm REALLY bad at explaining... so I took pictures of the problems that I'm well, having problems with! I don't know what else to do, it's three thirty in the morning and I have not been to bed yet, and have been awake since 4 AM YESTERDAY working on this non-stop... and I CAN'T FIGURE IT OUT?! Am I just that stupid?!?! ... please please PLEASE help me...

    How do I solve these?!

    1-3. http://i259.photobucket.com/albums/h...DSC_0354-1.jpg

    4-5.
    http://i259.photobucket.com/albums/h...s/DSC_0355.jpg

    6.
    http://i259.photobucket.com/albums/h...s/DSC_0356.jpg

    7.
    http://i259.photobucket.com/albums/h...s/DSC_0357.jpg

    8-9.
    http://i259.photobucket.com/albums/h...s/DSC_0358.jpg

    I know it's a lot, but believe me, I've spent SO MUCH TIME on these and I just DON'T GET IT! and if they're not done by March 1st... .... my life is over. and I pay a lot of money... big time.
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  2. #2
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    Quote Originally Posted by oXCryssieLeahXo View Post
    So I'm REALLY bad at explaining... so I took pictures of the problems that I'm well, having problems with! I don't know what else to do, it's three thirty in the morning and I have not been to bed yet, and have been awake since 4 AM YESTERDAY working on this non-stop... and I CAN'T FIGURE IT OUT?! Am I just that stupid?!?! ... please please PLEASE help me...

    How do I solve these?!

    1-3. http://i259.photobucket.com/albums/h...DSC_0354-1.jpg

    4-5.
    http://i259.photobucket.com/albums/h...s/DSC_0355.jpg

    6.
    http://i259.photobucket.com/albums/h...s/DSC_0356.jpg

    7.
    http://i259.photobucket.com/albums/h...s/DSC_0357.jpg

    8-9.
    http://i259.photobucket.com/albums/h...s/DSC_0358.jpg

    I know it's a lot, but believe me, I've spent SO MUCH TIME on these and I just DON'T GET IT! and if they're not done by March 1st... .... my life is over. and I pay a lot of money... big time.
    answer for 6 is APD (over points B and C)

    and 8, 9 is pie
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  3. #3
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    Quote Originally Posted by oXCryssieLeahXo View Post
    So I'm REALLY bad at explaining... so I took pictures of the problems that I'm well, having problems with! I don't know what else to do, it's three thirty in the morning and I have not been to bed yet, and have been awake since 4 AM YESTERDAY working on this non-stop... and I CAN'T FIGURE IT OUT?! Am I just that stupid?!?! ... please please PLEASE help me...

    How do I solve these?!

    ...
    To answer 1.-3. you need the following formulas:

    a^2 = f \cdot c .............. b^2 = d \cdot c

    e^2 = f \cdot d .............. e = \frac{a \cdot b}{c}

    to #7:

    \overline{PX} = r = 9 ~\implies~\overline{PY} = 15

    You are dealing with a right triangle:

    \overline{WY} = \sqrt{15^2 - 9^2} = 12


    EDIT: It looks like as if you are living in Germany. If so: Im Anhang finden Sie eine komplette Liste aller Formeln im rechtwinkligen Dreieck (I've attached a list of the formulas concerning a right triangle)
    Attached Files Attached Files
    Last edited by earboth; February 28th 2008 at 10:13 PM.
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  4. #4
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    I'll help you with 4:

    Question 4

    The simple answer to this is 20 degrees. Why? Well, this is one of the circle theorems you should have come across called the angles subtended by the same arc theorem. Basically, this means that the angle directly above ACB is the same. This goes for DAC and DBC.

    ACB = ADB
    DAC = DBC

    ----

    As for question 5, I'm not too certain what the 100 is referring to so I cannot really help you there.
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  5. #5
    Newbie oXCryssieLeahXo's Avatar
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    Smile Danke!!

    Quote Originally Posted by earboth View Post


    EDIT: It looks like as if you are living in Germany. If so: Im Anhang finden Sie eine komplette Liste aller Formeln im rechtwinkligen Dreieck (I've attached a list of the formulas concerning a right triangle)
    Ja ich bin eine Deutsche. =]] Vielen VIELEN lieben dank für die datei!!!!
    Sehr nett!
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  6. #6
    Newbie oXCryssieLeahXo's Avatar
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    Smile thank yah!

    Quote Originally Posted by ArmiAldi View Post
    answer for 6 is APD (over points B and C)

    and 8, 9 is pie
    thank you so sooo much!!!
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  7. #7
    Newbie oXCryssieLeahXo's Avatar
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    Smile Thx!!!

    Quote Originally Posted by sqleung View Post
    I'll help you with 4:

    Question 4

    The simple answer to this is 20 degrees. Why? Well, this is one of the circle theorems you should have come across called the angles subtended by the same arc theorem. Basically, this means that the angle directly above ACB is the same. This goes for DAC and DBC.

    ACB = ADB
    DAC = DBC

    ----

    As for question 5, I'm not too certain what the 100 is referring to so I cannot really help you there.
    Thank you SO MUCH too. This is so helpful! =]] Ahh thanks!
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