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Math Help - Equable shapes/Formulae

  1. #1
    Newbie mememe_fun91's Avatar
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    Equable shapes/Formulae

    Ok I have this Maths courseowrk that has to be in tomorow and i've only done the simplest parts and now i need help coz my teacher will kill me if i dont kill myself first!

    Anyway, so, i need to know the formula for the area/volume of these shapes in x/y form:
    Paralellogram
    Cylinder
    Regular pentagon
    Right angled triangle (shortest lengths x and y)
    Isosceles triangle
    Square based pyramid
    Cone


    And then i need help with how to work out the equation e.g:

    Cirlce - Area = Pi*r≤
    Circumference = 2*Pi*r

    2*Pi*r = Pi*r≤ (/r)(/Pi)
    r = 2

    Rectangle - Perimeter = 2x + 2y
    Area = xy

    xy = 2x + 2y (-2x)
    xy - 2x = 2y
    x (y - 2) = 2y (/ (y - 2))
    x = 2y / y - 2

    If anyone can help it would be amazing!!!
    Thanks x
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  2. #2
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    For formulae, Area and Volume Formula for geometrical figures.


    Specify your problem which you donít get.
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  3. #3
    Newbie mememe_fun91's Avatar
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    I don't know how to work through the equations eg:

    So looking at the site i've been given i need to do -

    Parallelogram-
    2x + 2y = x * h

    I have a worksheet from my teacher that tells me the answers but I dont know how to get to the answer which is x = 2y / (h - 2)
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  4. #4
    Forum Admin topsquark's Avatar
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    Quote Originally Posted by mememe_fun91 View Post
    I don't know how to work through the equations eg:

    So looking at the site i've been given i need to do -

    Parallelogram-
    2x + 2y = x * h

    I have a worksheet from my teacher that tells me the answers but I dont know how to get to the answer which is x = 2y / (h - 2)
    2x + 2y = xh

    -xh + 2x + 2y = -xh + xh

    -xh + 2x + 2y = 0

    -xh + 2x + 2y - 2y = 0 - 2y

    -xh + 2x = -2y

    x(-h + 2) = -2y

    \frac{1}{-h + 2} \cdot x(-h + 2) =  \frac{1}{-h + 2} \cdot (-2y)

    x = \frac{-2y}{-h + 2}

    x = \frac{-2y}{-h + 2} \cdot \frac{-1}{-1}

    x = \frac{2y}{h - 2}

    -Dan
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