1. ## Check with my equation Please...(area of figures)

1. A regular hexagon with side 12.
To find the height or the apothem..my equation:
h²+ 6² = 12²
h²+ 36 = 144
h²= 108
h= 6√3
Then to find the area of the regular hexagon...by formula of A=1/2ap,my equation is...
A= (1/2)(6√3)(72)
I got the equation up to here, but i have no idea of how to multiply the radical.....help with this please...(multiplying the radical...)
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1. A regular pentagon with side S and apothem(=radius)3.

2. If ∆ ABC is similar to ∆ ADE, find the probability that a point selected at random from ∆ ABC will lie inside quadrilateral BDEC....?

3. Find the area of a square with diagonal √6 meters.

4. Find the area of a square with radius 3√2.

5. Find the area of an equilateral triangle with height 4√3.

6. Find the area of a regular pentagon with side 2x and apothem 1/2y.

7.The bisectors of the angles of triangle DEF intersect in a point that is equidistant from ?, ?, and ?.

8. In triangle GHI, the perpendicular bisectores segment GH, HI, and GI intersect at point Z. Name three congruent segments.

2. Originally Posted by sarayork
A= (1/2)(6√3)(72)
I have no idea of how to multiply the radical...
I expect you do have an idea. You are letting the radical intimidate you. Be strong!

(1/2)(6√3)(72) = (1/2)*(6)*(72)*(sqrt(3)) = 216*sqrt(3)

That's it. About which part of that did you have no idea?

3. Originally Posted by TKHunny
I expect you do have an idea. You are letting the radical intimidate you. Be strong!

(1/2)(6√3)(72) = (1/2)*(6)*(72)*(sqrt(3)) = 216*sqrt(3)

That's it. About which part of that did you have no idea?