Thread: Check with my equation Please...(area of figures)

1. A regular hexagon with side 12.
To find the height or the apothem..my equation:
h²+ 6² = 12²
h²+ 36 = 144
h²= 108
h= 6√3
Then to find the area of the regular hexagon...by formula of A=1/2ap,my equation is...
A= (1/2)(6√3)(72)
I got the equation up to here, but i have no idea of how to multiply the radical.....help with this please...(multiplying the radical...)
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Then please answer this question...
1. A regular pentagon with side S and apothem(=radius)3.

2. If ∆ ABC is similar to ∆ ADE, find the probability that a point selected at random from ∆ ABC will lie inside quadrilateral BDEC....?

3. Find the area of a square with diagonal √6 meters.

4. Find the area of a square with radius 3√2.

5. Find the area of an equilateral triangle with height 4√3.

6. Find the area of a regular pentagon with side 2x and apothem 1/2y.

7.The bisectors of the angles of triangle DEF intersect in a point that is equidistant from ?, ?, and ?.

8. In triangle GHI, the perpendicular bisectores segment GH, HI, and GI intersect at point Z. Name three congruent segments.


***PLEASE HELP ME..........ㅠㅠ***

Originally Posted by sarayork

A= (1/2)(6√3)(72)
I have no idea of how to multiply the radical...

I expect you do have an idea. You are letting the radical intimidate you. Be strong!

(1/2)(6√3)(72) = (1/2)*(6)*(72)*(sqrt(3)) = 216*sqrt(3)

That's it. About which part of that did you have no idea?

Originally Posted by TKHunny

I expect you do have an idea. You are letting the radical intimidate you. Be strong!

(1/2)(6√3)(72) = (1/2)*(6)*(72)*(sqrt(3)) = 216*sqrt(3)

That's it. About which part of that did you have no idea?

I had no idea about the multiplying the radicals ....so the answer to that one is 216√3 right? haha...I see...Thanks alot~!!^0^*