Hello,
If we put all the four equations given by SlipEternal in the Wolfram computational intelligence It gave the answer for the four unknown variables as follows $z(v)=26.4979,w=3.50207,x=5.31243,y=22.2655$. So the area of triangle assuming $base=y+4=26.2655,height=w=3.50207,$ we get the area of triangle 45.99 using the formula of the area of triangle $[\frac12*base*height]$ which is wrong and different from the correct answer 60
Can someone confirm that there are two possible triangles that fit the requirements, both having an area of 60 ?
(All dimensions approximate, 4dp)
(1) AB =13.7262, BC = 8.7423, CA = 16.2738, /_BAC = 32.4933 deg.
(2) AB = 4.8666, BC = 24.6577, CA = 25.1334, /_BAC = 78.8351 deg.
Hello,
The WolframAlpha computational intelligence gave these four solutions 1)v≈26.4979, w≈3.50207, x≈-5.31643, y≈22.2655;2)v≈26.4979, w≈3.50207, x≈5.31643, y≈22.2655;
3)v≈34.5687, w≈-4.56873, x≈-6.07234, y≈-38.2655; 4)v≈34.5687, w≈-4.56873, x≈-6.07234, y≈-38.2655.
Now tell me which two solutions are acceptable?
Secondly, You are telling $\overline{AN}$ is not the angle bisector. But your answer confirms that $\overline{AN}$ is the angle bisector and its length is 14.2971.
So, WolframAlpha gave wrong answers.