Came across this annoying problem:
Determine amt. (gal.) of water per hr. delivered through a 6" pipe, inside diameter 6.065".
Water travels at 10' per sec. 1 gallon = 231 cu. in.
Anybody understand it?
I ended up with ~54,000 gal. per hr.
Came across this annoying problem:
Determine amt. (gal.) of water per hr. delivered through a 6" pipe, inside diameter 6.065".
Water travels at 10' per sec. 1 gallon = 231 cu. in.
Anybody understand it?
I ended up with ~54,000 gal. per hr.
Here are my calculations:
The cross-sectional area of water is:
$$\pi\cdot \left( \dfrac{6.065}{2}\right)^2 \text{ in}^2$$
Area times positional velocity gives volume per time:
$$\pi\cdot \left(\dfrac{6.065}{2}\right)^2\text{ in}^2\cdot \left(10\text{ ft/sec}\right)\cdot \left(12\text{ in/ft}\right) \cdot \left( 3600\text{ sec/hr}\right) \cdot \left( 1/231\text{ gal/in}^3 \right) \approx 54,000 \text{ gal/hr}$$
I get the same answer as you.