3/2 = m/4 = n/3
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Yes, triangle ABC is similar to triangle BDC.
Originally Posted by HallsofIvy Yes, triangle ABC is similar to triangle BDC. Ok . Thank you. I thought triangle ABD is similar to triangel BDC.
Originally Posted by Syndy Ok . Thank you. I thought triangle ABD is similar to triangel BDC. Make sure you can prove that! Assuming on an exam is not a good idea. -Dan
Originally Posted by topsquark Make sure you can prove that! Assuming on an exam is not a good idea. -Dan Klaatu barada nikto.
Originally Posted by Syndy 3/2 = m/4 = n/3 From the given $\Delta ABC \approx \Delta BDC$ (NOTE the order of the letters. That is important.) Then read off: $\dfrac{AC}{BC}=\dfrac{n+2}{4},~\dfrac{AB}{BD}= \dfrac {m}{3}~\&~\dfrac{BC}{DC}=\dfrac{4}{2}$
Originally Posted by Plato From the given $\Delta ABC \approx \Delta BDC$ (NOTE the order of the letters. That is important.) Then read off: $\dfrac{AC}{BC}=\dfrac{n+2}{4},~\dfrac{AB}{BD}= \dfrac {m}{3}~\&~\dfrac{BC}{DC}=\dfrac{4}{2}$ Thank you very much.