A circle in the standard (x,y) coordinate plane has center (3,8) and is tangent to the x-axis. The point (x,y) in on the circle if and only if x and y satisfy which of the follwing equations?
The solution is (x - 3)^2 + (y - 8)^2 = 64. Why do we say the radius is 8? Why couldn't it be 3 with the above information?
Hello, Sarah!
Did you make a sketch?
A circle in the standard (x,y) coordinate plane
has center (3,8) and is tangent to the x-axis.
The point (x,y) in on the circle if and only if x and y satisfy which of the follwing equations?
The solution is (x - 3)^2 + (y - 8)^2 = 64.
Why do we say the radius is 8?
Why couldn't it be 3 with the above information?Code:| | * * * * * * | * * | * | * | (3,8) * * | * * * | : * | : * | : * * | : * * : * - - - + - * * * - - - - - - |