# Thread: [ASK] Parallelogram in Cuboid

1. ## [ASK] Parallelogram in Cuboid

In an ABCD.EFGH cuboid with AB = 4 cm, BC = 3 cm, and CG = 5 cm there is a parallelogram OBFPH with O is located at the center of ABCD and P is located at the center of EFGH. The distance between the lines HO and PB is ....
A. $\displaystyle 5\sqrt3$ cm
B. $\displaystyle 5\sqrt2$ cm
C. $\displaystyle \sqrt5$ cm
D. $\displaystyle \frac{5}{2}\sqrt2$ cm
E. $\displaystyle \frac{5}{3}\sqrt3$ cm

By making use of the parallelogram formula, I got $\displaystyle \frac{1}{5}\sqrt5$. Do you guys get the same answer as me or any of the options?

2. ## Re: [ASK] Parallelogram in Cuboid

Hey Monoxdifly.

You might want to draw a diagram and post your explanation step by step if you are looking for extended feedback on your answer.

Do you know how to explain your answer in terms of more fundamental geometry? I am saying this because you will probably get marked down if you don't.

3. ## Re: [ASK] Parallelogram in Cuboid

This is not even my homework. I am tutoring a boy and he chose this question and the answer we did isn't in any of the options. But it turned out we were right (confirmed in other math forums).