Hi!Can anyone help me with this?
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WHAT is the question? You gave us an equation only...
We have to proof that (4R+r)^9>=....
Originally Posted by AlexC We have to proof that (4R+r)^9>=.... What are we given about $\Delta ABC~?$ Is it simply any triangle? Some authors use $R$ for the circumradius and $r$ for the inradius. Is that the case here?
Sorry, i found out that the problem was wrong. The correct problem is: In triangle Abc. Prove that (4R+r)^9>=19683/4*(R^2*p^6*r)
Last edited by AlexC; Mar 10th 2018 at 03:34 PM.
Sorry. This is the correct problem. ABC is a simply any triangle
Originally Posted by AlexC Sorry. This is the correct problem. ABC is a simply any triangle That is a useless posting. Why not just post the entire question with all details?
This is the entire question with all details. In any triangle ABC, we have to proof that (4R+r)^9>=... where r:inradius and R: circumradius and p- semiperimeter
Last edited by AlexC; Mar 10th 2018 at 05:09 PM.