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Thread: triangle edge and distance of vertice to bisector intersection

  1. #1
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    triangle edge and distance of vertice to bisector intersection

    I am not sure how to geometrically prove: In a triangle ABC, if the bisector of angle A intersects the edge BC at a point D, then AB > BD and AC > CD.
    Last edited by mghorba; Jul 6th 2017 at 11:32 AM.
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  2. #2
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    Re: triangle edge and distance of vertice to bisector intersection

    \frac{\text{BD}}{\text{AB}}=\frac{\text{CD}}{\text  {AC}}=\frac{\text{BD}+\text{CD}}{\text{AB}+\text{A  C}}=\frac{\text{BC}}{\text{AB}+\text{AC}}<1
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    Re: triangle edge and distance of vertice to bisector intersection

    Thanks.
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