Hi all,
In diag belo I have to find length of red triangle.
1). Equation x^2 + y^ = 9 Do i make y^2 subject here? And place in y^2 below:
(12- x^2)^2 - (9- y^2)^2 = c^2 ?
The three equations:
$x^2+y^2=3^2$
$(12-x)^2+(9-y)^2=z^2$
$xy+(12-x)(9-y)+3z = 12\cdot 9$
The last equation comes from adding up areas.
This gives $z \approx. 12.2553$