Corners of a triangle ABC is A(-2,5),B(4,2) and C(x,0).For the

perimeter of the triangle to be minimum what must be the value of x?

MY WORK:

I found the answer as -16/7 according to the book -24/7.

I found the slope of AB as 3/2. For perimeter to be minimum A-B-C must

be collinear. So -2/x+4=3/2,and x=-16/7