ABC is a triangle

|AB|=|ED|

|BC|=|EC|

Angle BAC=10

find angle EDC=x?

My work:

I drew EK parallel to AB.

I drew EB so EBD is isosceles.

Angle ABE=a

Angle EBD=b

Angle AKD=a+b

Angle CEK=10

Angle BEK=a

I extended AC and drew a line from B intersecting AC at

F.Triangle BCF. Angle BCF=Angle ECD.BF=ED and BC=EC. I am

sure triangles are congruent but I can't prove that.