1. ## Angles

ABC is a triangle.
|DK|=|DC|
angle ABD=angle FAC=20 degrees
angle DBC=angle ACB=40 degrees

Find Angle BCK.

Any work?

3. ## Re: Angles

My work:
Angle BDC=100 degrees
I connected B to K so DBK is isosceles.
Triangle DKC is isosceles and angle DKC=40+x
Angle AFC=120 degrees
Angle BKC=135 degrees.
I took angle CBK as y so
x+y=50 degrees.
Triangle AEDis isosceles.
ABD is equialteral.
ABD is isosceles

I did.

5. ## Re: Angles

I first wrote the question after that posted my work.

6. ## Re: Angles

Originally Posted by kastamonu
I first wrote the question after that posted my work.
Next time, post BOTH at same time...
(else we'll have you arrested and jailed)

OK.

8. ## Re: Angles

If I can find angel DFA the work will be done. I need help. According to the book answer is 35.

9. ## Re: Angles

ABF equilateral
BF = AB

ABD isosceles
BD = AB

Therefore BD = BF

BDF isosceles
angle BDF = 70 degrees

10. ## Re: Angles

Yes you are right. I was looking for a circle. You saved my time. Many Thanks. I will send another one.