ABC is a triangle.
|DK|=|DC|
angle ABD=angle FAC=20 degrees
angle DBC=angle ACB=40 degrees
Find Angle BCK.
My work:
Angle BDC=100 degrees
I connected B to K so DBK is isosceles.
Triangle DKC is isosceles and angle DKC=40+x
Angle AFC=120 degrees
Angle BKC=135 degrees.
I took angle CBK as y so
x+y=50 degrees.
Angle ADB=80 degrees.
Triangle AEDis isosceles.
ABD is equialteral.
ABD is isosceles