The following link will take you to a file that has a screenshot of my problem. I'm not allowed to use trig.
https://drive.google.com/file/d/0B9q...=sharing(Rofl)
The following link will take you to a file that has a screenshot of my problem. I'm not allowed to use trig.
https://drive.google.com/file/d/0B9q...=sharing(Rofl)
I'm not sure why you would "label the vertex at the 'x' F" when it is already labeled "E". Oh, I see. DenisB is not referring to the "x degrees" that you are to determine, he is referring to the point where the two line segments, AE and BD, intersect.
I would use the fact that the measures of the angles in a triangle sum to 180 degrees repeatedly. You are given that angle BAE has measure 60 degrees and angle ABD has measure 50, angle AFB has measure 180- 60- 50= 70 degrees. By the 'vertical angle theorem', angle DFE is also 70 degrees. We have that angle ABE has measure 50+ 30= 80 degrees so angle 180- 60- 80= 40 degrees. There are many more triangles- keep doing that.
I did that, and this is where I got. https://docs.google.com/a/tsc.k12.in...it?usp=sharing