Express x in terms of the other variables in the diagram below:
l.
r l ' ' , .
l h l ' , .
l_______l____>
x t
Assuming that is a (poorly drawn) triangle and angle XR and TH are right angles.
Hello, white_cap!
We have two similar right triangles.Express $\displaystyle x$ in terms of the other variables in the diagram below:Code:* | * | * r| | * | |h * | | * * - - - * - - - - - - - * x t
Hence: .$\displaystyle \frac{x+t}{r} \:=\:\frac{t}{h}$
Solve for $\displaystyle x\!:\;\;x + t \:=\:\frac{rt}{h}\quad\Rightarrow\quad x \;=\;\frac{rt}{h} - t$
Therefore: .$\displaystyle x \;=\;\frac{t(r-h)}{h}$