A,E,D are collinear.
m(ACB)=50
m(ABC)=40
m(CBD)=70
m(BCD)=65
m(BDA)=?
Do you know anything about $m(\angle AEB), m(\angle AEC), m(\angle BED),\text{ or } m(\angle CED)$? So far, I know that $m(\angle BAC) = 90^\circ$ and $m(\angle BDC) = 45^\circ$. There is not enough information to know $m(\angle BDA)$.
https://14773644510176710490.googleg...smXH8VW5CZN-Wc
This is the original.
You're dreaming in Technicolor!
Stop making wild guesses and start drawing
your diagrams to scale: what you're showing is a mess!
Drawing a median from A makes no sense.
Answer is 25 degrees.
Also, angleBAD = angleCAD = 45 degrees.
And angleCED = 95 degrees, angleBED = 85 degrees.