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Thread: is this wrong?

  1. #1
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    is this wrong?

    A,E,D are collinear.
    m(ACB)=50
    m(ABC)=40
    m(CBD)=70
    m(BCD)=65
    m(BDA)=?
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  2. #2
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    Re: is this wrong?

    I do not understand your notation. What is the $m$ function, how does it turn three letters into number? Is it the measure of the angle in degrees? Is it the area of the triangle formed by the three vertices? Need a little more here.
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  3. #3
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    Re: is this wrong?

    Angle ACB.It is not a function. They are angle degrees.
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  4. #4
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    Re: is this wrong?

    Do you know anything about $m(\angle AEB), m(\angle AEC), m(\angle BED),\text{ or } m(\angle CED)$? So far, I know that $m(\angle BAC) = 90^\circ$ and $m(\angle BDC) = 45^\circ$. There is not enough information to know $m(\angle BDA)$.
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  5. #5
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    Re: is this wrong?

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  6. #6
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    Re: is this wrong?

    Quote Originally Posted by kastamonu View Post
    Can you translate? is that a kite?
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  7. #7
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    Re: is this wrong?

    No it is not a kite.
    A,E,D are collinear.
    Angle(ACB)=50 degrees
    Angle(ABC)=40 degrees
    Angle(CBD)=70 degrees
    Angle(BCD)=65 degrees
    m(BDA)=?
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  8. #8
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    Re: is this wrong?

    According to the messages there is an angel bisector but I couldn't see it.The question is ok. I translated all.
    Last edited by kastamonu; May 11th 2017 at 03:59 PM.
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  9. #9
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    Re: is this wrong?

    Maybe we must use the incredible trio.There is a right angle there.
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  10. #10
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    Re: is this wrong?

    Quote Originally Posted by kastamonu View Post
    Maybe we must use the incredible trio.There is a right angle there.
    It is very clear that$\angle BAC$ is a right angle.
    But I agree with Slip, there is not sufficient information to answer the question.
    Is $\overline{AD}$ an angular bisector?
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  11. #11
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    Re: is this wrong?

    Answer: angle ADB = 25 degrees.
    Did it this way:
    Assign value 1 to AB.
    Use Sine Law 3 times.
    Use Cosine law once.

    angleADB = ASIN[SIN(110) / AD] = 25

    AD = ~2.2235
    Thanks from SlipEternal
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  12. #12
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    Re: is this wrong?

    We can draw a median through A. A is a right angle. We will get isosceles triangles by this way. Answer is 30 degrees.
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  13. #13
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    Re: is this wrong?

    You're dreaming in Technicolor!
    Stop making wild guesses and start drawing
    your diagrams to scale: what you're showing is a mess!
    Drawing a median from A makes no sense.

    Answer is 25 degrees.

    Also, angleBAD = angleCAD = 45 degrees.

    And angleCED = 95 degrees, angleBED = 85 degrees.
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  14. #14
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    Re: is this wrong?

    Yes I will check it again. I can make a mistake but you don't have any right to insult. You are talking behind a keyboard. You can use a better language.
    Last edited by kastamonu; May 12th 2017 at 11:18 AM.
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  15. #15
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    Re: is this wrong?

    Boy oh boy...see if I care...
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