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Thread: is this wrong?

  1. #16
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    Re: is this wrong?

    Care or not.You are just a ill-mannered person. I didn't ask your idea but you are coming without invitation and insulting. I don't know who you are and I don't care.
    Last edited by kastamonu; May 12th 2017 at 11:28 AM.
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  2. #17
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    Re: is this wrong?

    Quote Originally Posted by kastamonu View Post
    Yes I will check it again. I can make a mistake but you don't have any right to insult. You are talking behind a keyboard. You can use a better language.
    What insult? I insulted the diagram, not you!

    Another point:
    you are expected to show your work when posting a problem:
    this is a rule at math help sites.

    You showed no work with this problem:
    we do not provide full solutions.
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  3. #18
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    Re: is this wrong?

    I will check the question and will send a solution.
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  4. #19
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    Re: is this wrong?

    Quote Originally Posted by kastamonu View Post
    I will check the question and will send a solution.
    We thank you very much for your anticipated co-operation.

    May I suggest that you show the diagram this way:
    point A at origin
    point B on x-axis
    point C on y-axis, such that angle ACB = 50 degrees
    now point D (which will be easy)
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  5. #20
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    Re: is this wrong?

    Answer is 25 but there must be another way.
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  6. #21
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    Re: is this wrong?

    Quote Originally Posted by kastamonu View Post
    Answer is 25 but there must be another way.
    PLEASE define "another way".
    Are you guessing there is another way?
    PLEASE be advised that guessing is not part of mathematics.

    You now state that answer is 25:
    PLEASE show your work to arrive at that result.
    We thank you in advance for your co-operation.
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  7. #22
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    Re: is this wrong?

    I will send my work if I can find the answer. There must be a way other than trigonometry. I will try to find it.
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  8. #23
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    Re: is this wrong?

    Quote Originally Posted by kastamonu View Post
    There must be a way other than trigonometry.
    PLEASE define "must".
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  9. #24
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    Re: is this wrong?

    If I find an answer you will see it.
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  10. #25
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    Re: is this wrong?

    BAC is a right angle. Let's draw the circumcircle of triangle ABC; BC is a diameter. Let E be the point
    where CD intersects this circle; then angle BEC is also a right angle. BED is a right isosceles triangle, and EB = ED. If
    we can show that EA = BE, so that E is the circumcenter of triangle
    ABD, we can solve the question easily.
    Last edited by kastamonu; May 13th 2017 at 12:03 PM.
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  11. #26
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    Re: is this wrong?

    Quote Originally Posted by kastamonu View Post
    If we can show that EA = BE, so that E is the circumcenter
    of triangle ABD, we can solve the question easily.
    Impossible: angleBAE = 45, angleABE = 40.

    You can't do stuff that changes the "givens".
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  12. #27
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    Re: is this wrong?

    E is not the old E. I made a typo. Take it as F.
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  13. #28
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    Re: is this wrong?

    Do you have any question?
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  14. #29
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    Re: is this wrong?

    IF FA=FB, F will be the circumcircle.In fact a very hard question you have to think about 2 circles.
    Last edited by kastamonu; May 13th 2017 at 01:55 PM.
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