i have worked out so far angle ADC and angle ASC=180 as its a cyclic quadrilateral. also 2*angle ADC= angle ABC so angle ABC= 180-180+angle ADC so ABC=ADC ABC=ADC
i have worked out so far angle ADC and angle ASC=180 as its a cyclic quadrilateral. also 2*angle ADC= angle ABC so angle ABC= 180-180+angle ADC so ABC=ADC ABC=ADC
2*angle ADC= angle ABC is not correct but rather
2*angle ADC= angle AOC where O is the center of the circle through the points A,S,C,D
how do you get ABC=180-.5ASC using angles on the same arc thorem i get 2ADC=ABC so ADC=.5ABC i know ADC+ASC=180 so .5ABC=180-ASC this differs to ABC=180-.5ASC
how do you get ABC=180-.5ASC using angles on the same arc thorem i get 2ADC=ABC so ADC=.5ABC i know ADC+ASC=180 so .5ABC=180-ASC this differs to ABC=180-.5ASC
$m \angle{ASC}$ is read "the measure of angle ASC"
$\angle{ASC}$ is a central angle in the smaller circle. A central angle is equal to the measure of its intercepted arc. The intercepted arc is $arc \, ABC$