a triangle ABC is such that AB = 12 and AC = 8. X is the midpoint of the base BC. If the area of the triangle is 72, what is the length of the perpendicular from X to AB and to AC?

thanks

jacs

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- Apr 27th 2006, 01:20 AMjacsanother triangle area proof
a triangle ABC is such that AB = 12 and AC = 8. X is the midpoint of the base BC. If the area of the triangle is 72, what is the length of the perpendicular from X to AB and to AC?

thanks

jacs - Apr 27th 2006, 02:32 AMCaptainBlackQuote:

Originally Posted by**jacs**

so u=12. Then the length of the perp from X onto AB is u/2=6 (similar

triangles).

Drop a perp from B onto AC, call its length v, then Area(ABC)=8.v/2=72,

so v=18. Then the length of the perp from X onto AC is v/2=9 (similar

triangles).

RonL - Apr 27th 2006, 05:07 AMjacs
thanks a lot, that works beautifully, appreciate your help.