Thread: a coal bunker... HELLP QUICK!

i need to find the volume of a coal bunker,

Split the bunker up into a rectangular prism and a triangular solid.

The volume of the base or rectangular solid is: $\displaystyle 60*80*80 = 384,000$

The volume of the top of triangular solid is: $\displaystyle \frac{1}{2}*40*80*80 = 128,000$

Add these two separate volumes together for the total volume of the "rhombuslis prismus": $\displaystyle 384,000+128,000=512,000$

thanks so much! a guy called mr fantastic just reported me... O_o... y? i dont get it...

THERE IS A SAINT OF MATHS... YOU.

Originally Posted by Hatake_Naussica

thanks so much! a guy called mr fantastic just reported me... O_o... y? i dont get it...

THERE IS A SAINT OF MATHS... YOU.

Well, I actually replied too quickly. I should have not given you the answer straight up. We are not here to supply you answers for your homeworks, quizzes, and/or tests. We are here to help you learn. Let this be a lesson learned for both of us. You should not ask for answers straight up, and with how your question was stated, I shouldn't have given you one.

Hello, Hatake_Naussica!

The front face is a trapezoid with parallel sides 60 and 100, and height 60.
Find its area.

Then multiply by the "thickness", 80.