i need to find the volume of a coal bunker,

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- Jan 14th 2008, 05:31 AMHatake_Naussicaa coal bunker... HELLP QUICK!
i need to find the volume of a coal bunker,

- Jan 14th 2008, 05:35 AMcolby2152
Split the bunker up into a rectangular prism and a triangular solid.

The volume of the base or rectangular solid is: $\displaystyle 60*80*80 = 384,000$

The volume of the top of triangular solid is: $\displaystyle \frac{1}{2}*40*80*80 = 128,000$

Add these two separate volumes together for the total volume of the "rhombuslis prismus": $\displaystyle 384,000+128,000=512,000$ - Jan 14th 2008, 05:38 AMHatake_NaussicaThank You
thanks so much! a guy called mr fantastic just reported me... O_o... y? i dont get it...

THERE IS A SAINT OF MATHS... YOU.:D - Jan 14th 2008, 05:50 AMcolby2152
Well, I actually replied too quickly. I should have not given you the answer straight up. We are not here to supply you answers for your homeworks, quizzes, and/or tests. We are here to help you learn. Let this be a lesson learned for both of us. You should not ask for answers straight up, and with how your question was stated, I shouldn't have given you one.

- Jan 14th 2008, 06:50 AMSoroban
Hello, Hatake_Naussica!

The front face is a trapezoid with parallel sides 60 and 100, and height 60.

Find its area.

Then multiply by the "thickness", 80.