a circle passes through the points (0,-3) and (0,3) and has radius 5
find equations of possible solutions (two possible)
realllyyy confused even though it's probably quite simple, even unsure where to begin
A circle has a center (h,k) and a radius r in the formula
(x-h)^2 + (y-k)^2=r^2. You will end up with two equations when plugging in your information:
1) (0-h)^2 + (-3-k)^2 = 5^2
2) (0-h)^2 + (+3-k)^2 = 5^2
Try to solve for h and k from using the system of two quadratics equations...
How can 5 + 3 = 8/2 = 4?
Look at the outsides of this: 5 + 3 = 4 This is obviously not true! You need to write the expressions correctly, so this needs to go on two lines:
5 + 3 = 8
8/2 = 4
Okay, pet peeve rant over.