Suppose we are given an isosceles triangle ABC in the coordinate plane R^2 whose vertices are given by A = (o, h), B= (-x, 0), and C= (x, 0). Then the point J where the angle bisectors meet lies on the y-axis. Find its
I tried to approach this problem by taking the square of a, letting a = tan beta x. is that the correct way? Thank you so much for the help.