If length of two identical sides is L and the angle between them is θ, the area is
hi i need to find the angle theta that maximizes the area of the isosceles triangle with legs length L. Once I can get a formula, I am fine to calculate the derivatives and determine the maximum, but my trig is a little rusty, especially with angles.
I need to know how to find the formula to express the area in terms of the angle, theta (theta is between the two identical sides of the isosceles).
thanks