Help please!

Solve for x:

(x+2)(x-5)=6x+x^2-5

x^2+2x-15=0

2x^2-11x=-3

http://i4.photobucket.com/albums/y10.../flowchart.jpg

http://i4.photobucket.com/albums/y10.../perimeter.jpg

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- Dec 4th 2007, 04:22 PMpeachgalperimeter, flowcharts, and equations
Help please!

Solve for x:

(x+2)(x-5)=6x+x^2-5

x^2+2x-15=0

2x^2-11x=-3

http://i4.photobucket.com/albums/y10.../flowchart.jpg

http://i4.photobucket.com/albums/y10.../perimeter.jpg - Dec 5th 2007, 04:38 AMearboth
Hello,

if a quadratic equation has the form:

then the solutions are:

Transcribe all the equations to the form given above and use the formula. As an example:

The first equation isn't a quadratic equation!

= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =

http://i4.photobucket.com/albums/y10.../flowchart.jpg

I can't draw a flow chart here so I'll list the steps which has to be done:

1. Calculate . Sum of intern angles of a triangle is 180°.

2. Calculate . Sum of intern angles of a triangle is 180°.

3. Corresponding intern angles are equal thus the triangles are similar.

4. Proportion of corresponding sides is a constant:

. Solve for x.

Use proportions:

. Solve for x.

You are dealing with an isoscele right triangle thus

= = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = = =

http://i4.photobucket.com/albums/y10.../perimeter.jpg[/QUOTE]

to a) Since the angle at the base of the right triangle is 45° you are dealing with an isoscele triangle. Therefore the other leg of the right angle is 7 mm too and the length of the hypotenuse is

Therefore the perimeter is

to b) The length of top and base line together is 30 m. That is only possible if the base line is translated by 6 m to the right. The parallelogramm consists of 2 right triangles with the legs 12 m and 9 m and a rectangle with l = 9m and w = 6 m. The hypotenuse of the right triangles is: . Thus the perimeter of the parallelogramm is

to c) Split the figur into a rectangle with l = 7'' and w = 6'' and a right triangle. One leg of the right angle is 11'' - 7'' = 4''.

Since one angle is 60° the angle at the top of the right triangle is 30°. Therefore the hypotenuse is twice as long as the opposite side of the 30°-angle. h = 8''

The vertical leg v of the right triangle is:

The perimeter of the figur is: