There are 2 similar triangles. one small triangle and a larger one. The small one has sides that are 15, 20, and 25. on the big one in the same order, 24, y, and x. How do I find x and y?
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Originally Posted by robin1 There are 2 similar triangles. one small triangle and a larger one. The small one has sides that are 15, 20, and 25. on the big one in the same order, 24, y, and x. How do I find x and y? do you have diagrams? for the triangle with sides 24,x and y, which is the smallest, middle and largest side? are we to assume 24 < y < x ?
I do have diagrams. The small triangle, 15 is the shortest 20 is middle and 25 is longest. The big triangle, 24 is the shortest, y is middle and x is longest.
Originally Posted by robin1 I do have diagrams. The small triangle, 15 is the shortest 20 is middle and 25 is longest. The big triangle, 24 is the shortest, y is middle and x is longest. the triangles are similar, thus their side lengths are proportional. that is, for instance: and
then I come up with: 25 = x 12 24 and 20 = y 15 24 How do I now solve this?
Originally Posted by robin1 then I come up with: 25 = x 12 24 and 20 = y 15 24 How do I now solve this? you tell me let's start with how would we isolate x? that is, get x on one side of the equation by itself. that is, get rid of the 24 that is dividing it?
Last edited by Jhevon; Dec 4th 2007 at 03:14 PM. Reason: Had 12 instead of 15... I trust too much
it is actually: 25 = x 15 24 then 20 = y 15 24 I think that I need to cross multiply 25*24 15x 15x=600 x=40 20*24 15y 15y=480 y=32
Originally Posted by robin1 it is actually: 25 = x 15 24 then 20 = y 15 24 I think that I need to cross multiply 25*24 15x 15x=600 x=40 20*24 15y 15y=480 y=32 correct
Thank You so much!!!!
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