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Math Help - I need to find the values of x and y.

  1. #1
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    I need to find the values of x and y.

    There are 2 similar triangles.

    one small triangle and a larger one.
    The small one has sides that are 15, 20, and 25.
    on the big one in the same order, 24, y, and x.

    How do I find x and y?
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by robin1 View Post
    There are 2 similar triangles.

    one small triangle and a larger one.
    The small one has sides that are 15, 20, and 25.
    on the big one in the same order, 24, y, and x.

    How do I find x and y?
    do you have diagrams? for the triangle with sides 24,x and y, which is the smallest, middle and largest side? are we to assume 24 < y < x ?
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  3. #3
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    value of x and y

    I do have diagrams.

    The small triangle, 15 is the shortest 20 is middle and 25 is longest.
    The big triangle, 24 is the shortest, y is middle and x is longest.
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  4. #4
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by robin1 View Post
    I do have diagrams.

    The small triangle, 15 is the shortest 20 is middle and 25 is longest.
    The big triangle, 24 is the shortest, y is middle and x is longest.
    the triangles are similar, thus their side lengths are proportional. that is, for instance:

    \frac {\mbox{The longest side of the small triangle}}{\mbox{The shortest side of the small triangle}} = \frac {\mbox{The longest side of the large triangle}}{\mbox{The shortest side of the large triangle}}

    and

    \frac {\mbox{The middle side of the small triangle}}{\mbox{The shortest side of the small triangle}} = \frac {\mbox{The middle side of the large triangle}}{\mbox{The shortest side of the large triangle}}
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  5. #5
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    value of x and y

    then I come up with:
    25 = x
    12 24

    and
    20 = y
    15 24

    How do I now solve this?
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  6. #6
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by robin1 View Post
    then I come up with:
    25 = x
    12 24

    and
    20 = y
    15 24

    How do I now solve this?
    you tell me

    let's start with \frac {25}{15} = \frac x{24}

    how would we isolate x? that is, get x on one side of the equation by itself. that is, get rid of the 24 that is dividing it?
    Last edited by Jhevon; December 4th 2007 at 02:14 PM. Reason: Had 12 instead of 15... I trust too much
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  7. #7
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    value of x and y

    it is actually:

    25 = x
    15 24

    then
    20 = y
    15 24

    I think that I need to cross multiply
    25*24
    15x
    15x=600
    x=40

    20*24
    15y
    15y=480
    y=32
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  8. #8
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by robin1 View Post
    it is actually:

    25 = x
    15 24

    then
    20 = y
    15 24

    I think that I need to cross multiply
    25*24
    15x
    15x=600
    x=40

    20*24
    15y
    15y=480
    y=32
    correct
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  9. #9
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    value of x and y

    Thank You so much!!!!
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